y^3/7/y^-1/2

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Solution for y^3/7/y^-1/2 equation: 


D( y )

y = 0

y^-1 = 0

y = 0

y = 0

y^-1 = 0

y^-1 = 0

1*y^-1 = 0 // : 1

y^-1 = 0

y należy do O

y in (-oo:0) U (0:+oo)

(((y^3)/7)/(y^-1))/2 = 0

1/14*y^4 = 0 // : 1/14

y^4 = 0

y = 0

y in { 0} 

y belongs to the empty set

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